Help: Who's Good At Math?

coldLBZ

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Apr 22, 2007
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I'm studying so I can get my 3rd class steam ticket, and I'm stumped. I have to solve the following:

y(1+3x)+[3x(x-y)-{-2(x-1)+3x2}-y]

Bold "2" is supposed to be superscript, should be x squared I think. It's been so long since I've done this. Thanks. :confused:

My book says the answer is 2x-2, how did they get that?
 

MMLMM

Tunergeek
Mar 2, 2008
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www.dyncal.com
I'm studying so I can get my 3rd class steam ticket, and I'm stumped. I have to solve the following:

y(1+3x)+[3x(x-y)-{-2(x-1)+3x2}-y]

Bold "2" is supposed to be superscript, should be x squared I think. It's been so long since I've done this. Thanks. :confused:

My book says the answer is 2x-2, how did they get that?

i think the book is wrong, lol
 

JoshH

Daggum farm truck
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Feb 14, 2007
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y(1+3x)+(3x(x-y)-(-2(x-1)+3x^2)-y)=
y+3xy+(3x^2-3xy-(-2x+2+3x^2)-y)=
y+3xy+3x^2-3xy+2x-2-3x^2-y=

Now then, can you figure it out from there?
 

coldLBZ

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Apr 22, 2007
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Thanks for the help guys, I understand what you guys did, I just have to wrap my head around it, with your help I got 2x-2 as well.:cool:
 

LBZ DMAX

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Nov 7, 2006
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yup...once you factor everything out, you get...

a^2+4a+4 - 6a^2-10a-4...then simply add for the answer of...

-5a^2+14a+8...

Damn, it's been about 6-7 years since I've done this stuff...haha
 

coldLBZ

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Apr 22, 2007
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yup...once you factor everything out, you get...

a^2+4a+4 - 6a^2-10a-4...then simply add for the answer of...

-5a^2+14a+8...

Damn, it's been about 6-7 years since I've done this stuff...haha


I think I see what you're trying to say, using the formulas that nosliw posted I ended up with a^2+4a+4 - 6a^2-10a-4. Then the - 6a^2 and the a^2 combine to make -5a^2, am I right so far? Then I added the 4a to the 10a and that gave me -5a^2+14a, so far so good? I am left with 4- (-4) which = +8. That makes -5a^2+14a+8. Is my thought process correct on this?

Thanks again for the help guys, I appreciate it. :)